68.49+22.22y(0.003811-y)=100-17.24y(1+y)

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Solution for 68.49+22.22y(0.003811-y)=100-17.24y(1+y) equation:



68.49+22.22y(0.003811-y)=100-17.24y(1+y)
We move all terms to the left:
68.49+22.22y(0.003811-y)-(100-17.24y(1+y))=0
We add all the numbers together, and all the variables
22.22y(-1y+0.003811)-(100-17.24y(y+1))+68.49=0
We multiply parentheses
-22y^2+0.083842y-(100-17.24y(y+1))+68.49=0
We calculate terms in parentheses: -(100-17.24y(y+1)), so:
100-17.24y(y+1)
determiningTheFunctionDomain -17.24y(y+1)+100
We multiply parentheses
-17y^2-17y+100
Back to the equation:
-(-17y^2-17y+100)
We get rid of parentheses
-22y^2+17y^2+17y+0.083842y-100+68.49=0
We add all the numbers together, and all the variables
-5y^2+17.083842y-31.51=0
a = -5; b = 17.083842; c = -31.51;
Δ = b2-4ac
Δ = 17.0838422-4·(-5)·(-31.51)
Δ = -338.34234251904
Delta is less than zero, so there is no solution for the equation

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