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68.96=4d(d+5)
We move all terms to the left:
68.96-(4d(d+5))=0
We calculate terms in parentheses: -(4d(d+5)), so:We get rid of parentheses
4d(d+5)
We multiply parentheses
4d^2+20d
Back to the equation:
-(4d^2+20d)
-4d^2-20d+68.96=0
a = -4; b = -20; c = +68.96;
Δ = b2-4ac
Δ = -202-4·(-4)·68.96
Δ = 1503.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-\sqrt{1503.36}}{2*-4}=\frac{20-\sqrt{1503.36}}{-8} $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+\sqrt{1503.36}}{2*-4}=\frac{20+\sqrt{1503.36}}{-8} $
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