68=(-10b)+8

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Solution for 68=(-10b)+8 equation: 



68=(-10b)+8

We move all terms to the left:

68-((-10b)+8)=0



We calculate terms in parentheses: -((-10b)+8), so:

(-10b)+8

We get rid of parentheses

-10b+8

Back to the equation:

-(-10b+8)



We get rid of parentheses

10b-8+68=0

We add all the numbers together, and all the variables

10b+60=0

We move all terms containing b to the left, all other terms to the right

10b=-60

b=-60/10

b=-6

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