68=(1/5)(20x

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Solution for 68=(1/5)(20x equation: 



68=(1/5)(20x

We move all terms to the left:

68-((1/5)(20x)=0



Domain of the equation: 5)20x+68!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+1/5)20x+68=0

We multiply all the terms by the denominator


-((+1=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

Równanie nie ma rozwiązania

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