68=(2+3x)

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Solution for 68=(2+3x) equation: 



68=(2+3x)

We move all terms to the left:

68-((2+3x))=0

We add all the numbers together, and all the variables

-((3x+2))+68=0



We calculate terms in parentheses: -((3x+2)), so:

(3x+2)

We get rid of parentheses

3x+2

Back to the equation:

-(3x+2)



We get rid of parentheses

-3x-2+68=0

We add all the numbers together, and all the variables

-3x+66=0

We move all terms containing x to the left, all other terms to the right

-3x=-66

x=-66/-3

x=+22

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