68=(2x+10)

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Solution for 68=(2x+10) equation: 



68=(2x+10)

We move all terms to the left:

68-((2x+10))=0



We calculate terms in parentheses: -((2x+10)), so:

(2x+10)

We get rid of parentheses

2x+10

Back to the equation:

-(2x+10)



We get rid of parentheses

-2x-10+68=0

We add all the numbers together, and all the variables

-2x+58=0

We move all terms containing x to the left, all other terms to the right

-2x=-58

x=-58/-2

x=+29

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