68=1/5(20r+50)+2

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Solution for 68=1/5(20r+50)+2 equation: 



68=1/5(20r+50)+2

We move all terms to the left:

68-(1/5(20r+50)+2)=0



Domain of the equation: 5(20r+50)+2)!=0

r∈R



We multiply all the terms by the denominator


-(1+68*5(20r+50)+2)=0



We calculate terms in parentheses: -(1+68*5(20r+50)+2), so:

1+68*5(20r+50)+2

determiningTheFunctionDomain
68*5(20r+50)+1+2

We add all the numbers together, and all the variables

68*5(20r+50)+3

Wy multiply elements

340r(2+3

Back to the equation:

-(340r(2+3)



We add all the numbers together, and all the variables

-(340r5=0

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