68=1/5(20x+50)+3

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Solution for 68=1/5(20x+50)+3 equation: 



68=1/5(20x+50)+3

We move all terms to the left:

68-(1/5(20x+50)+3)=0



Domain of the equation: 5(20x+50)+3)!=0

x∈R



We multiply all the terms by the denominator


-(1+68*5(20x+50)+3)=0



We calculate terms in parentheses: -(1+68*5(20x+50)+3), so:

1+68*5(20x+50)+3

determiningTheFunctionDomain
68*5(20x+50)+1+3

We add all the numbers together, and all the variables

68*5(20x+50)+4

Wy multiply elements

340x(2+4

Back to the equation:

-(340x(2+4)



We add all the numbers together, and all the variables

-(340x6=0

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