68=1/5(20x+50)+5

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Solution for 68=1/5(20x+50)+5 equation: 



68=1/5(20x+50)+5

We move all terms to the left:

68-(1/5(20x+50)+5)=0



Domain of the equation: 5(20x+50)+5)!=0

x∈R



We multiply all the terms by the denominator


-(1+68*5(20x+50)+5)=0



We calculate terms in parentheses: -(1+68*5(20x+50)+5), so:

1+68*5(20x+50)+5

determiningTheFunctionDomain
68*5(20x+50)+1+5

We add all the numbers together, and all the variables

68*5(20x+50)+6

Wy multiply elements

340x(2+6

Back to the equation:

-(340x(2+6)



We add all the numbers together, and all the variables

-(340x8=0

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