68=12+c

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Solution for 68=12+c equation: 



68=12+c

We move all terms to the left:

68-(12+c)=0

We add all the numbers together, and all the variables

-(c+12)+68=0

We get rid of parentheses

-c-12+68=0

We add all the numbers together, and all the variables

-1c+56=0

We move all terms containing c to the left, all other terms to the right

-c=-56

c=-56/-1

c=+56

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