68=2(2x-2)+2x

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Solution for 68=2(2x-2)+2x equation: 



68=2(2x-2)+2x

We move all terms to the left:

68-(2(2x-2)+2x)=0



We calculate terms in parentheses: -(2(2x-2)+2x), so:

2(2x-2)+2x

We add all the numbers together, and all the variables

2x+2(2x-2)

We multiply parentheses

2x+4x-4

We add all the numbers together, and all the variables

6x-4

Back to the equation:

-(6x-4)



We get rid of parentheses

-6x+4+68=0

We add all the numbers together, and all the variables

-6x+72=0

We move all terms containing x to the left, all other terms to the right

-6x=-72

x=-72/-6

x=+12

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