68=2(6x-4)+5(x+2)

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Solution for 68=2(6x-4)+5(x+2) equation: 



68=2(6x-4)+5(x+2)

We move all terms to the left:

68-(2(6x-4)+5(x+2))=0



We calculate terms in parentheses: -(2(6x-4)+5(x+2)), so:

2(6x-4)+5(x+2)

We multiply parentheses

12x+5x-8+10

We add all the numbers together, and all the variables

17x+2

Back to the equation:

-(17x+2)



We get rid of parentheses

-17x-2+68=0

We add all the numbers together, and all the variables

-17x+66=0

We move all terms containing x to the left, all other terms to the right

-17x=-66

x=-66/-17

x=3+15/17

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