68=2(x-4)-8(1-5x)

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Solution for 68=2(x-4)-8(1-5x) equation: 



68=2(x-4)-8(1-5x)

We move all terms to the left:

68-(2(x-4)-8(1-5x))=0

We add all the numbers together, and all the variables

-(2(x-4)-8(-5x+1))+68=0



We calculate terms in parentheses: -(2(x-4)-8(-5x+1)), so:

2(x-4)-8(-5x+1)

We multiply parentheses

2x+40x-8-8

We add all the numbers together, and all the variables

42x-16

Back to the equation:

-(42x-16)



We get rid of parentheses

-42x+16+68=0

We add all the numbers together, and all the variables

-42x+84=0

We move all terms containing x to the left, all other terms to the right

-42x=-84

x=-84/-42

x=+2

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