68=20+3b

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Solution for 68=20+3b equation: 



68=20+3b

We move all terms to the left:

68-(20+3b)=0

We add all the numbers together, and all the variables

-(3b+20)+68=0

We get rid of parentheses

-3b-20+68=0

We add all the numbers together, and all the variables

-3b+48=0

We move all terms containing b to the left, all other terms to the right

-3b=-48

b=-48/-3

b=+16

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