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68=28-5x(x-3)
We move all terms to the left:
68-(28-5x(x-3))=0
We calculate terms in parentheses: -(28-5x(x-3)), so:We get rid of parentheses
28-5x(x-3)
determiningTheFunctionDomain -5x(x-3)+28
We multiply parentheses
-5x^2+15x+28
Back to the equation:
-(-5x^2+15x+28)
5x^2-15x-28+68=0
We add all the numbers together, and all the variables
5x^2-15x+40=0
a = 5; b = -15; c = +40;
Δ = b2-4ac
Δ = -152-4·5·40
Δ = -575
Delta is less than zero, so there is no solution for the equation
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