68=3(6x-1)-7(1-3x)

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Solution for 68=3(6x-1)-7(1-3x) equation: 



68=3(6x-1)-7(1-3x)

We move all terms to the left:

68-(3(6x-1)-7(1-3x))=0

We add all the numbers together, and all the variables

-(3(6x-1)-7(-3x+1))+68=0



We calculate terms in parentheses: -(3(6x-1)-7(-3x+1)), so:

3(6x-1)-7(-3x+1)

We multiply parentheses

18x+21x-3-7

We add all the numbers together, and all the variables

39x-10

Back to the equation:

-(39x-10)



We get rid of parentheses

-39x+10+68=0

We add all the numbers together, and all the variables

-39x+78=0

We move all terms containing x to the left, all other terms to the right

-39x=-78

x=-78/-39

x=+2

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