68=3x+2(-6x-20)

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Solution for 68=3x+2(-6x-20) equation:



68=3x+2(-6x-20)
We move all terms to the left:
68-(3x+2(-6x-20))=0
We calculate terms in parentheses: -(3x+2(-6x-20)), so:
3x+2(-6x-20)
We multiply parentheses
3x-12x-40
We add all the numbers together, and all the variables
-9x-40
Back to the equation:
-(-9x-40)
We get rid of parentheses
9x+40+68=0
We add all the numbers together, and all the variables
9x+108=0
We move all terms containing x to the left, all other terms to the right
9x=-108
x=-108/9
x=-12

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