68=3x+2(-6x-20)

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Solution for 68=3x+2(-6x-20) equation: 



68=3x+2(-6x-20)

We move all terms to the left:

68-(3x+2(-6x-20))=0



We calculate terms in parentheses: -(3x+2(-6x-20)), so:

3x+2(-6x-20)

We multiply parentheses

3x-12x-40

We add all the numbers together, and all the variables

-9x-40

Back to the equation:

-(-9x-40)



We get rid of parentheses

9x+40+68=0

We add all the numbers together, and all the variables

9x+108=0

We move all terms containing x to the left, all other terms to the right

9x=-108

x=-108/9

x=-12

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