68=4(7)(2)+2(2)(h)

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Solution for 68=4(7)(2)+2(2)(h) equation: 



68=4(7)(2)+2(2)(h)

We move all terms to the left:

68-(4(7)(2)+2(2)(h))=0

We add all the numbers together, and all the variables

-(22h+472)+68=0

We get rid of parentheses

-22h-472+68=0

We add all the numbers together, and all the variables

-22h-404=0

We move all terms containing h to the left, all other terms to the right

-22h=404

h=404/-22

h=-18+4/11

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