68=8(1+3x)-20X

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Solution for 68=8(1+3x)-20X equation: 



68=8(1+3x)-20x

We move all terms to the left:

68-(8(1+3x)-20x)=0

We add all the numbers together, and all the variables

-(8(3x+1)-20x)+68=0



We calculate terms in parentheses: -(8(3x+1)-20x), so:

8(3x+1)-20x

We add all the numbers together, and all the variables

-20x+8(3x+1)

We multiply parentheses

-20x+24x+8

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We get rid of parentheses

-4x-8+68=0

We add all the numbers together, and all the variables

-4x+60=0

We move all terms containing x to the left, all other terms to the right

-4x=-60

x=-60/-4

x=+15

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