68=y2

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Solution for 68=y2 equation:



68=y2
We move all terms to the left:
68-(y2)=0
We add all the numbers together, and all the variables
-1y^2+68=0
a = -1; b = 0; c = +68;
Δ = b2-4ac
Δ = 02-4·(-1)·68
Δ = 272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{272}=\sqrt{16*17}=\sqrt{16}*\sqrt{17}=4\sqrt{17}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{17}}{2*-1}=\frac{0-4\sqrt{17}}{-2} =-\frac{4\sqrt{17}}{-2} =-\frac{2\sqrt{17}}{-1} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{17}}{2*-1}=\frac{0+4\sqrt{17}}{-2} =\frac{4\sqrt{17}}{-2} =\frac{2\sqrt{17}}{-1} $

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