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6=(-2/3)(7x-2)
We move all terms to the left:
6-((-2/3)(7x-2))=0
Domain of the equation: 3)(7x-2))!=0We multiply parentheses ..
x∈R
-((-14x^2-2/3*-2))+6=0
We multiply all the terms by the denominator
-((-14x^2-2+6*3*-2))=0
We calculate terms in parentheses: -((-14x^2-2+6*3*-2)), so:We get rid of parentheses
(-14x^2-2+6*3*-2)
We get rid of parentheses
-14x^2-2-2+6*3*
We add all the numbers together, and all the variables
-14x^2
Back to the equation:
-(-14x^2)
14x^2=0
a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{28}=0$
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