6=(1/2)z

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Solution for 6=(1/2)z equation: 



6=(1/2)z

We move all terms to the left:

6-((1/2)z)=0



Domain of the equation: 2)z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-((+1/2)z)+6=0

We multiply all the terms by the denominator


-((+1+6*2)z)=0



We calculate terms in parentheses: -((+1+6*2)z), so:

(+1+6*2)z

We add all the numbers together, and all the variables

13z

Back to the equation:

-(13z)



z=0/-13

z=0

Równanie nie ma rozwiązania

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