6=(1/4)z-1

Solution for 6=(1/4)z-1 equation:

6=(1/4)z-1

We move all terms to the left:

6-((1/4)z-1)=0


Domain of the equation: 4)z-1)!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

-((+1/4)z-1)+6=0

We multiply all the terms by the denominator


-((+1+6*4)z-1)=0


We calculate terms in parentheses: -((+1+6*4)z-1), so:

(+1+6*4)z-1

We add all the numbers together, and all the variables

25z-1

Back to the equation:

-(25z-1)


We get rid of parentheses

-25z+1=0

We move all terms containing z to the left, all other terms to the right

-25z=-1

z=-1/-25

z=1/25