6=(3/2+3y)

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Solution for 6=(3/2+3y) equation: 



6=(3/2+3y)

We move all terms to the left:

6-((3/2+3y))=0



Domain of the equation: 2+3y))!=0

We move all terms containing y to the left, all other terms to the right

3y))!=-2

y!=-2/1

y!=-2

y∈R



We add all the numbers together, and all the variables

-((+3y+3/2))+6=0

We multiply all the terms by the denominator


-((+3y+3+6*2))=0



We calculate terms in parentheses: -((+3y+3+6*2)), so:

(+3y+3+6*2)

We add all the numbers together, and all the variables

(3y+15)

We get rid of parentheses

3y+15

Back to the equation:

-(3y+15)



We get rid of parentheses

-3y-15=0

We move all terms containing y to the left, all other terms to the right

-3y=15

y=15/-3

y=-5

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