6=(3/4)(10x+16)

Solution for 6=(3/4)(10x+16) equation:

6=(3/4)(10x+16)

We move all terms to the left:

6-((3/4)(10x+16))=0


Domain of the equation: 4)(10x+16))!=0

x∈R


We add all the numbers together, and all the variables

-((+3/4)(10x+16))+6=0

We multiply parentheses ..

-((+30x^2+3/4*16))+6=0

We multiply all the terms by the denominator


-((+30x^2+3+6*4*16))=0


We calculate terms in parentheses: -((+30x^2+3+6*4*16)), so:

(+30x^2+3+6*4*16)

We get rid of parentheses

30x^2+3+6*4*16

We add all the numbers together, and all the variables

30x^2+387

Back to the equation:

-(30x^2+387)


We get rid of parentheses

-30x^2-387=0

a = -30; b = 0; c = -387;
Δ = b2-4ac
Δ = 02-4·(-30)·(-387)
Δ = -46440
Delta is less than zero, so there is no solution for the equation