6=(3n-1)=4(n+4)

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Solution for 6=(3n-1)=4(n+4) equation: 



6=(3n-1)=4(n+4)

We move all terms to the left:

6-((3n-1))=0



We calculate terms in parentheses: -((3n-1)), so:

(3n-1)

We get rid of parentheses

3n-1

Back to the equation:

-(3n-1)



We get rid of parentheses

-3n+1+6=0

We add all the numbers together, and all the variables

-3n+7=0

We move all terms containing n to the left, all other terms to the right

-3n=-7

n=-7/-3

n=2+1/3

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