6=(3y-2y+7)

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Solution for 6=(3y-2y+7) equation: 



6=(3y-2y+7)

We move all terms to the left:

6-((3y-2y+7))=0

We add all the numbers together, and all the variables

-((y+7))+6=0



We calculate terms in parentheses: -((y+7)), so:

(y+7)

We get rid of parentheses

y+7

Back to the equation:

-(y+7)



We get rid of parentheses

-y-7+6=0

We add all the numbers together, and all the variables

-1y-1=0

We move all terms containing y to the left, all other terms to the right

-y=1

y=1/-1

y=-1

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