6=(40/7)+c

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Solution for 6=(40/7)+c equation: 



6=(40/7)+c

We move all terms to the left:

6-((40/7)+c)=0



Domain of the equation: 7)+c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+40/7)+c)+6=0

We multiply all the terms by the denominator


-((+40+6*7)+c)=0



We calculate terms in parentheses: -((+40+6*7)+c), so:

(+40+6*7)+c

determiningTheFunctionDomain
c+(+40+6*7)

We add all the numbers together, and all the variables

c+82

Back to the equation:

-(c+82)



We get rid of parentheses

-c-82=0

We add all the numbers together, and all the variables

-1c-82=0

We move all terms containing c to the left, all other terms to the right

-c=82

c=82/-1

c=-82

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