6=(9+2+z)/3

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Solution for 6=(9+2+z)/3 equation: 



6=(9+2+z)/3

We move all terms to the left:

6-((9+2+z)/3)=0

We add all the numbers together, and all the variables

-((z+11)/3)+6=0

We multiply all the terms by the denominator


-((z+11)+6*3)=0



We calculate terms in parentheses: -((z+11)+6*3), so:

(z+11)+6*3

We add all the numbers together, and all the variables

(z+11)+18

We get rid of parentheses

z+11+18

We add all the numbers together, and all the variables

z+29

Back to the equation:

-(z+29)



We get rid of parentheses

-z-29=0

We add all the numbers together, and all the variables

-1z-29=0

We move all terms containing z to the left, all other terms to the right

-z=29

z=29/-1

z=-29

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