6=(a+2)-3=9a-15

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Solution for 6=(a+2)-3=9a-15 equation: 



6=(a+2)-3=9a-15

We move all terms to the left:

6-((a+2)-3)=0



We calculate terms in parentheses: -((a+2)-3), so:

(a+2)-3

We get rid of parentheses

a+2-3

We add all the numbers together, and all the variables

a-1

Back to the equation:

-(a-1)



We get rid of parentheses

-a+1+6=0

We add all the numbers together, and all the variables

-1a+7=0

We move all terms containing a to the left, all other terms to the right

-a=-7

a=-7/-1

a=+7

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