6=-(3/5)(a-7)

Solution for 6=-(3/5)(a-7) equation:

6=-(3/5)(a-7)

We move all terms to the left:

6-(-(3/5)(a-7))=0


Domain of the equation: 5)(a-7))!=0

a∈R


We add all the numbers together, and all the variables

-(-(+3/5)(a-7))+6=0

We multiply parentheses ..

-(-(+3a^2+3/5*-7))+6=0

We multiply all the terms by the denominator


-(-(+3a^2+3+6*5*-7))=0


We calculate terms in parentheses: -(-(+3a^2+3+6*5*-7)), so:

-(+3a^2+3+6*5*-7)

We get rid of parentheses

-3a^2-3+7-6*5*

We add all the numbers together, and all the variables

-3a^2

Back to the equation:

-(-3a^2)


We get rid of parentheses

3a^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$a=\frac{-b}{2a}=\frac{0}{6}=0$