6=-2(3x-5)+5(x-2)

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Solution for 6=-2(3x-5)+5(x-2) equation: 



6=-2(3x-5)+5(x-2)

We move all terms to the left:

6-(-2(3x-5)+5(x-2))=0



We calculate terms in parentheses: -(-2(3x-5)+5(x-2)), so:

-2(3x-5)+5(x-2)

We multiply parentheses

-6x+5x+10-10

We add all the numbers together, and all the variables

-x

Back to the equation:

-(-x)



We add all the numbers together, and all the variables

-(-1x)+6=0

We get rid of parentheses

1x+6=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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