6=-3(c2+2)

Solution for 6=-3(c2+2) equation:

6=-3(c2+2)

We move all terms to the left:

6-(-3(c2+2))=0

We add all the numbers together, and all the variables

-(-3(+c^2+2))+6=0


We calculate terms in parentheses: -(-3(+c^2+2)), so:

-3(+c^2+2)

We multiply parentheses

-3c^2-6

Back to the equation:

-(-3c^2-6)


We get rid of parentheses

3c^2+6+6=0

We add all the numbers together, and all the variables

3c^2+12=0

a = 3; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·3·12
Δ = -144
Delta is less than zero, so there is no solution for the equation