6=-4(1+x)+3(x+1)

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Solution for 6=-4(1+x)+3(x+1) equation: 



6=-4(1+x)+3(x+1)

We move all terms to the left:

6-(-4(1+x)+3(x+1))=0

We add all the numbers together, and all the variables

-(-4(x+1)+3(x+1))+6=0



We calculate terms in parentheses: -(-4(x+1)+3(x+1)), so:

-4(x+1)+3(x+1)

We multiply parentheses

-4x+3x-4+3

We add all the numbers together, and all the variables

-1x-1

Back to the equation:

-(-1x-1)



We get rid of parentheses

1x+1+6=0

We add all the numbers together, and all the variables

x+7=0

We move all terms containing x to the left, all other terms to the right

x=-7

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