6=-5(1-x)+3(x+1)

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Solution for 6=-5(1-x)+3(x+1) equation: 



6=-5(1-x)+3(x+1)

We move all terms to the left:

6-(-5(1-x)+3(x+1))=0

We add all the numbers together, and all the variables

-(-5(-1x+1)+3(x+1))+6=0



We calculate terms in parentheses: -(-5(-1x+1)+3(x+1)), so:

-5(-1x+1)+3(x+1)

We multiply parentheses

5x+3x-5+3

We add all the numbers together, and all the variables

8x-2

Back to the equation:

-(8x-2)



We get rid of parentheses

-8x+2+6=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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