6=1/2z;z=

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Solution for 6=1/2z;z= equation: 



6=1/2zz=

We move all terms to the left:

6-(1/2zz)=0



Domain of the equation: 2zz)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

-(+1/2zz)+6=0

We get rid of parentheses

-1/2zz+6=0

We multiply all the terms by the denominator


6*2zz-1=0

Wy multiply elements

12z-1=0

We move all terms containing z to the left, all other terms to the right

12z=1

z=1/12

z=1/12

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