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6=1/3(1+x)
We move all terms to the left:
6-(1/3(1+x))=0
Domain of the equation: 3(1+x))!=0We add all the numbers together, and all the variables
x∈R
-(1/3(x+1))+6=0
We multiply all the terms by the denominator
-(1+6*3(x+1))=0
We calculate terms in parentheses: -(1+6*3(x+1)), so:
1+6*3(x+1)
determiningTheFunctionDomain 6*3(x+1)+1
Wy multiply elements
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Back to the equation:
-(18x(x+1)
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| y=1*2^24 | | 3/5y=-1/4 | | 6=p=10 | | -3(2j/3)-6)=32 | | -5x-8+12=3x-12 | | 13+4x=33 | | 9x+7x=35+29 | | (x-3)·(x-8)=0 | | 320=16x | | 6x+3-2=3(2x1)-4 | | 1.09x+190=469.04 | | 9-4a=180 | | 7x+8-7=15 | | 5w3=50 | | 6×(-9)=9.5(a-6.9) | | 1/4(20x-28=13 | | 55(x+1)=48× | | 7x+1-5=2(4x+3) | | 27=9.x | | 16=4v-12 | | (4/7x)/(6/13)=1 | | (4/7x)/(6/13)=0 | | 32/x+1=8/7 | | 2x-6-1=4x+5 | | 3+14=x+11 | | -19.7x12.4=-8.5x+15.6 | | 11x-7=11+7x-10 | | 13x-124=36+5x | | -3x-16=17-2x | | 3x-11=2x-12+20 | | 4h+9=3+-h+46) | | 64=15x-7x |