6=1/3(9p+12

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Solution for 6=1/3(9p+12 equation: 



6=1/3(9p+12

We move all terms to the left:

6-(1/3(9p+12)=0



Domain of the equation: 3(9p+12)+6!=0

We move all terms containing p to the left, all other terms to the right

3(9p+12)!=-6

p∈R



We multiply all the terms by the denominator


-(1=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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