6=1/3(9p+12)

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Solution for 6=1/3(9p+12) equation: 



6=1/3(9p+12)

We move all terms to the left:

6-(1/3(9p+12))=0



Domain of the equation: 3(9p+12))!=0

p∈R



We multiply all the terms by the denominator


-(1+6*3(9p+12))=0



We calculate terms in parentheses: -(1+6*3(9p+12)), so:

1+6*3(9p+12)

determiningTheFunctionDomain
6*3(9p+12)+1

Wy multiply elements

18p(9+1

Back to the equation:

-(18p(9+1)



We add all the numbers together, and all the variables

-(18p10=0

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