6=11(2x+4)=28

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Solution for 6=11(2x+4)=28 equation: 



6=11(2x+4)=28

We move all terms to the left:

6-(11(2x+4))=0



We calculate terms in parentheses: -(11(2x+4)), so:

11(2x+4)

We multiply parentheses

22x+44

Back to the equation:

-(22x+44)



We get rid of parentheses

-22x-44+6=0

We add all the numbers together, and all the variables

-22x-38=0

We move all terms containing x to the left, all other terms to the right

-22x=38

x=38/-22

x=-1+8/11

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