6=12+2z

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Solution for 6=12+2z equation: 



6=12+2z

We move all terms to the left:

6-(12+2z)=0

We add all the numbers together, and all the variables

-(2z+12)+6=0

We get rid of parentheses

-2z-12+6=0

We add all the numbers together, and all the variables

-2z-6=0

We move all terms containing z to the left, all other terms to the right

-2z=6

z=6/-2

z=-3

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