6=2(-2+x)-2(-2x-2)

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Solution for 6=2(-2+x)-2(-2x-2) equation: 



6=2(-2+x)-2(-2x-2)

We move all terms to the left:

6-(2(-2+x)-2(-2x-2))=0

We add all the numbers together, and all the variables

-(2(x-2)-2(-2x-2))+6=0



We calculate terms in parentheses: -(2(x-2)-2(-2x-2)), so:

2(x-2)-2(-2x-2)

We multiply parentheses

2x+4x-4+4

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We move all terms containing x to the left, all other terms to the right

-6x=-6

x=-6/-6

x=1

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