6=2(-2/3)+b

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Solution for 6=2(-2/3)+b equation: 



6=2(-2/3)+b

We move all terms to the left:

6-(2(-2/3)+b)=0



Domain of the equation: 3)+b)!=0

b!=0/1

b!=0

b∈R



We multiply all the terms by the denominator


-(2(-2+6*3)+b)=0



We calculate terms in parentheses: -(2(-2+6*3)+b), so:

2(-2+6*3)+b

determiningTheFunctionDomain
b+2(-2+6*3)

We add all the numbers together, and all the variables

b+216

Back to the equation:

-(b+216)



We get rid of parentheses

-b-216=0

We add all the numbers together, and all the variables

-1b-216=0

We move all terms containing b to the left, all other terms to the right

-b=216

b=216/-1

b=-216

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