6=2(1y+2)

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Solution for 6=2(1y+2) equation: 



6=2(1y+2)

We move all terms to the left:

6-(2(1y+2))=0

We add all the numbers together, and all the variables

-(2(y+2))+6=0



We calculate terms in parentheses: -(2(y+2)), so:

2(y+2)

We multiply parentheses

2y+4

Back to the equation:

-(2y+4)



We get rid of parentheses

-2y-4+6=0

We add all the numbers together, and all the variables

-2y+2=0

We move all terms containing y to the left, all other terms to the right

-2y=-2

y=-2/-2

y=1

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