6=2(2v+1)

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Solution for 6=2(2v+1) equation: 



6=2(2v+1)

We move all terms to the left:

6-(2(2v+1))=0



We calculate terms in parentheses: -(2(2v+1)), so:

2(2v+1)

We multiply parentheses

4v+2

Back to the equation:

-(4v+2)



We get rid of parentheses

-4v-2+6=0

We add all the numbers together, and all the variables

-4v+4=0

We move all terms containing v to the left, all other terms to the right

-4v=-4

v=-4/-4

v=1

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