6=2(3j-2)=4(1+j)

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Solution for 6=2(3j-2)=4(1+j) equation: 



6=2(3j-2)=4(1+j)

We move all terms to the left:

6-(2(3j-2))=0



We calculate terms in parentheses: -(2(3j-2)), so:

2(3j-2)

We multiply parentheses

6j-4

Back to the equation:

-(6j-4)



We get rid of parentheses

-6j+4+6=0

We add all the numbers together, and all the variables

-6j+10=0

We move all terms containing j to the left, all other terms to the right

-6j=-10

j=-10/-6

j=1+2/3

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