6=2(4k+3)+7

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Solution for 6=2(4k+3)+7 equation: 



6=2(4k+3)+7

We move all terms to the left:

6-(2(4k+3)+7)=0



We calculate terms in parentheses: -(2(4k+3)+7), so:

2(4k+3)+7

We multiply parentheses

8k+6+7

We add all the numbers together, and all the variables

8k+13

Back to the equation:

-(8k+13)



We get rid of parentheses

-8k-13+6=0

We add all the numbers together, and all the variables

-8k-7=0

We move all terms containing k to the left, all other terms to the right

-8k=7

k=7/-8

k=-7/8

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