6=2(b-4)-2(1-3b)

Solution for 6=2(b-4)-2(1-3b) equation:

6=2(b-4)-2(1-3b)

We move all terms to the left:

6-(2(b-4)-2(1-3b))=0

We add all the numbers together, and all the variables

-(2(b-4)-2(-3b+1))+6=0


We calculate terms in parentheses: -(2(b-4)-2(-3b+1)), so:

2(b-4)-2(-3b+1)

We multiply parentheses

2b+6b-8-2

We add all the numbers together, and all the variables

8b-10

Back to the equation:

-(8b-10)


We get rid of parentheses

-8b+10+6=0

We add all the numbers together, and all the variables

-8b+16=0

We move all terms containing b to the left, all other terms to the right

-8b=-16

b=-16/-8

b=+2