6=2(c+4)=4(c+2)

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Solution for 6=2(c+4)=4(c+2) equation: 



6=2(c+4)=4(c+2)

We move all terms to the left:

6-(2(c+4))=0



We calculate terms in parentheses: -(2(c+4)), so:

2(c+4)

We multiply parentheses

2c+8

Back to the equation:

-(2c+8)



We get rid of parentheses

-2c-8+6=0

We add all the numbers together, and all the variables

-2c-2=0

We move all terms containing c to the left, all other terms to the right

-2c=2

c=2/-2

c=-1

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