6=2(j-3)+2

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Solution for 6=2(j-3)+2 equation: 



6=2(j-3)+2

We move all terms to the left:

6-(2(j-3)+2)=0



We calculate terms in parentheses: -(2(j-3)+2), so:

2(j-3)+2

We multiply parentheses

2j-6+2

We add all the numbers together, and all the variables

2j-4

Back to the equation:

-(2j-4)



We get rid of parentheses

-2j+4+6=0

We add all the numbers together, and all the variables

-2j+10=0

We move all terms containing j to the left, all other terms to the right

-2j=-10

j=-10/-2

j=+5

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